Question:

How many mL of a 0.10 M NaOH solution are needed to neutralize 15 mL of 0.20 M H3PO4 solution?

Answer:

The reaction is 3 NaOH + H3PO4 -> Na3PO4 + 3 H20 So 0.0015 x 0.2 = 0.0003 moles of H3PO4 So we need 0.0003 x 3 = 0.0009 moles of NaOH The volume of NaOH needed is 0.0009/0.1 = 0.009 L So volume in mL is 0.009 x 1000 = 9 mL

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