How many grams of ethanol, C2H5OH, can be made by the fermentation of 1150 g of glucose, C6H12O6?


(1) 1150 g glucose/180 grams glucose per mole = 6.39 moles glucose (2) From the equation: (2moles ethanol/1mole glucose) x (6.39 moles glucose )= 12.79 moles ethanol produced (3) 12.79 moles ethanol x (46 grams ethanol/mole ethanol) = 587.78 g ethanol produced

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